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Fischer Esterification question

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Author Topic: Fischer Esterification question  (Read 1608 times)
katie7
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« on: June 25, 2009, 05:26:57 PM »

I have a couple of questions about Fischer esterification. I understand that Fischer esterification must happen in acidic conditions in order to give an appropriate leaving group (H2O not -OH) but I don't understand why it is the C=O oxygen that is protonated and not the C-OH oxygen?

My second question is say you had a molecule like para-aminobenzoic acid. Since N is both a better base and a better nucleophile than O, why would the N not be protonated by an acid catalyst instead of the O?

Thanks for your help!


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chrisf
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ChrisFNet


« Reply #1 on: June 26, 2009, 10:27:54 PM »
1

I will attempt to answer this question this weekend.
hey
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