Advertisements

Welcome to My Chemistry Tutor

Welcome, Guest. Please login or register.
Did you miss your activation email?

Login with username, password and session length

Search for Answers

Custom Search
Use our free chemistry search to search thousands of chemistry homework answers and tutorials

Ask a Question

If you did not find the answer to your chemistry question, join the community and ask for help.

Help Other Students

If you received chemistry help here why not try to help other students. You might undertand something that your peers are having trouble with. If you are in college chemistry you can likely help a high school chemistry student

Alkane Nomenclature

Pages: [1]
  Print  
Author Topic: Alkane Nomenclature  (Read 228 times)
susanbamboozlin
Labrat
*
Posts: 2




« on: January 27, 2010, 08:20:55 PM »

I am having some trouble with naming alkanes. I think I did the first two problems correctly, but I am not sure. I am having some trouble with the third one, and would greatly appreciate any help you can offer. I would like to have an explanation along with the answer so I can see what I did wrong! Thanks very much!

1. (CH3)2CHCH(CH3)2
4-carbon chain makes it butane
the branches at both C2 and C3 are methyl
so the name is 2,3-dimethylbutane

                         CH2Ch2CH2CH3
                         l
CH3CH2CH2CHCH2C--H
                l         l
            CH3CH2   H
6-carbon chain makes it hexane
branch at C2 is butyl
branch at C3 is ethyl
so the name is 2-butyl-3-ethylbutane.

3. This is the one I am very unsure of:
                      CH3 H
                        l    l
CH3CH2CH2CH2--C--C--CH2CH3
                        l     l
                       CH2 CH3
                        l
                       CH3

8-carbon chain= octane
branch at C3 is methyl
branches at 4C are methyl and ethyl
That is where I get stuck on the name. Is it 4-ethyl-4,3-dimethyloctane??

Thank you very much for your input!


Logged
freezard7734
Labrat
*
Posts: 16




« Reply #1 on: January 28, 2010, 08:31:33 AM »
1

The first one is correct. However, in the second one, you should use the longest C-branch as the base. There is a chain much longer than 6 carbons.
Actually, your third one seems fine...
hey
Logged
bhavna
Labrat
*
Posts: 12




« Reply #2 on: February 17, 2010, 09:52:29 PM »
2

Frist one is correct. Second ans should be, by selecting longest C chain which is decane; so it should be named as 4 ethly decane.
Thrid ans should be 3,4-dimethyl-4-ethyloctane, coz we should always select frist longest C chain & then numbering for groups should be in ascending orders as 1,2,3... & not as 3,2

hey
Logged
Pages: [1]
  Print  

 
Jump to:  

* Share this topic...
In a forum
(BBCode)
In a site/blog
(HTML)

Powered by MySQL Powered by PHP Powered by SMF 1.1.11 | SMF © 2006-2009, Simple Machines LLC Valid XHTML 1.0! Valid CSS!
MyChemistryTutor.com

Idea by BJR Technologies