thermodynamics

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[tinychar]

i need help with this question

A 50.0g sample of copper is heated to 96.2C and then placed in a calorimeter containing 75.0g of water at 19.6C. The specific heat capacity of copper is 0.20Jg/k and that of water is 4.18J g/k. Calculate the final temperature of the metal and water assuming that all of the heat is lost by the copper is gained by the water.

I came up with this (50.0)(0.20Jg/k)(x-96.2)=(74.0)(4.18Jg/k)(x-19.6)

but the equation doesnt' seem to work. someone help me please. pretty please

[mr_cochran]

Ask yourself, Did the copper gain or lose heat (temperature)?

Did the water gain or lose heat (temperature)?

Then double check your change in temperature, it should be

T_final - T_initial if gaining heat (temperature) and

T_initial - T_final if losing heat (temperature)