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Author Topic: 5.430g mixture of FeO and Fe3O4.  (Read 189 times)
flaca_1121
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« on: October 05, 2008, 06:26:54 PM »

You react this mixture with excess oxygen to form 5.779g of Fe2O3. Can you help me calculate the percent by mass of FeO in the original mixture.
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Otis
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« Reply #1 on: October 05, 2008, 07:48:46 PM »

Find the number of moles of iron in (5.779g) iron(III) oxide which should be the number of moles of iron to start with in the iron(II) oxide. I think we're missing some information, like the mass of the original mixture?

Otis
« Last Edit: October 07, 2008, 05:16:16 PM by Otis » Logged

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