[remeday86]

Hello, I am not sure if I did this right.

Write the net ionic equations that occur in the following cell:
Pb|Pb(NO3)2||AgNO3|Ag

My answer:

Ag(NO3)(aq) + Pb(s) --> Ag(s) + Pb(NO3)2(aq)


 ??? I am not sure how to figure this problem out.

[chemtopper]

Pb|Pb(NO3)2||AgNO3|Ag
this is the electrochemical cell and right side shows the reaction at cathode

2[AgNO3(aq)  + 1 electron -----> Ag (s)]   (reduction)

left side shows the reaction at anode
Pb(s)----------> Pb(NO3)2 (aq)+ 2 electrons        ( oxidation )
combine  both half reactions . Multiply reduction half reaction by 2 so that number of electrons transferred are same.


2AgNO3(aq) +Pb(s) ------> 2Ag (s) +Pb(NO3)2 (aq)
hey