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Author Topic: molarity, molality  (Read 87 times)
sugars225
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« on: January 27, 2010, 07:54:05 PM »

concentrated nitric acid solution has a density of  1.42g/mL, and is 69.0% HNO3 by mass

a) determine the molarity of the solution with respect to HNO3
b) molality of the solution with respect to HNO3

I calcualated the molarity to be  15.6mol/L but I do not get how to do b
« Last Edit: January 27, 2010, 07:55:53 PM by sugars225 » Logged
freezard7734
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« Reply #1 on: January 27, 2010, 08:33:50 PM »

Molality is simply the number of moles of solute divided by the number of kilograms of solvent.
To make life simpler, assume we are working with 1 L of solution. Then there are 1.42 kg of solution. 69% of that is HNO3, so from that you can get the number of moles of HNO3. Then 31% is water (solvent).
So molality is (moles of HNO3) / (.31 * 1.42 kg H2O) = 35.3 molal
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sugars225
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« Reply #2 on: January 27, 2010, 10:36:49 PM »

Thank you very much
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