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Author Topic: Molality  (Read 227 times)
sswa0322
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« on: December 12, 2009, 02:29:46 PM »

In this experiment, suppose that 1.10 grams of an unknown solid is added to 14.65 grams of naphthalene. The change in temperature of the freezing point for the experiment is determined to be 5.87 degrees Celsius. Calculate the molality of the solution. ( Kf for Napthalene = 6.80 c/m)
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kingchemist
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« Reply #1 on: December 13, 2009, 05:48:00 AM »

[delta]T = Kf * m where m = molality, Kf is the cryoscopic constant and [delta]T is the temperature change

So find molality (=moles/kg solvent)

You could go on to find the molar mass of the unknown though question does not ask for this
« Last Edit: December 13, 2009, 05:50:57 AM by kingchemist » Logged

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