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Freezing point depression

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Author Topic: Freezing point depression  (Read 863 times)
caseyj1155
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« on: June 23, 2009, 11:55:15 PM »

Could someone help explain this problem to me? :)

Since the freezing point of a solution depends on the relative nuhttp://www.mychemistrytutor.com/forums/college-chemistry/?action=postmber of particles, what would you calculate to be the freezing point of 0.1m solutions in water of a) NaCl b) BaCl2? ( Asusume that these salts are 100% ionized in solution. (Compare your answers with the actual respective freezing points : -0.348 degrees Celsius and -0.470 degrees Celsius. The difference is due to the decreased activity of the ions. Because of the attractive forces between the positively and negatively charged ions., they do not move completely  independently of one another)



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caseyj1155
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« Reply #1 on: June 24, 2009, 12:17:27 AM »
1

Here is another problem.

 how many grams of each of the following per kilogram of water in your car radiator are needed to give equal protection against freezing down to -10 degrees Celsius a) Methyl Alcohol, bp 64.6 degrees Celsius. B)  Ethylene glycol, bp 197.2 degrees.
hey
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