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Calculating gibbs free energy and equilibrium constant

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Author Topic: Calculating gibbs free energy and equilibrium constant  (Read 3193 times)
jnucka83
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« on: May 08, 2008, 10:56:22 AM »

Need to calculate gibbs free energy and equilibrium constant at 298K of

Mn04- + Fe+2 <--->  Fe+3 + Mn+2

I balance it to

MnO4- + 8H+ + 5Fe+2 <---> 5Mn+2 + 4H20 + 5Fe+3

K = [Mn+2][Fe+3]^5  /  [Mno4-][Mn+2]^5


i also know that G = -RTLnK


i dont have any other info please help!


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« Reply #1 on: May 08, 2008, 01:11:34 PM »
1

you should be able to look up thermodynamic data in the back of your book

you can look up Gibb's free energy for products and reactants

change in G = G products - G reactants

then solve for K
hey
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