Calculating gibbs free energy and equilibrium constant

[jnucka83]

Need to calculate gibbs free energy and equilibrium constant at 298K of

Mn04- + Fe+2 <--->  Fe+3 + Mn+2

I balance it to

MnO4- + 8H+ + 5Fe+2 <---> 5Mn+2 + 4H20 + 5Fe+3

K = [Mn+2][Fe+3]^5  /  [Mno4-][Mn+2]^5


i also know that G = -RTLnK


i dont have any other info please help!

[Chemistry Tutor]

you should be able to look up thermodynamic data in the back of your book

you can look up Gibb's free energy for products and reactants

change in G = G products - G reactants

then solve for K