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Calculating gibbs free energy and equilibrium constant
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Topic: Calculating gibbs free energy and equilibrium constant (Read 2556 times)
jnucka83
Labrat
Posts: 17
Calculating gibbs free energy and equilibrium constant
«
on:
May 08, 2008, 10:56:22 AM »
Need to calculate gibbs free energy and equilibrium constant at 298K of
Mn04- + Fe+2 <---> Fe+3 + Mn+2
I balance it to
MnO4- + 8H+ + 5Fe+2 <---> 5Mn+2 + 4H20 + 5Fe+3
K = [Mn+2][Fe+3]^5 / [Mno4-][Mn+2]^5
i also know that G = -RTLnK
i dont have any other info please help!
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Re: Calculating gibbs free energy and equilibrium constant
«
Reply #1 on:
May 08, 2008, 01:11:34 PM »
you should be able to look up thermodynamic data in the back of your book
you can look up Gibb's free energy for products and reactants
change in G = G products - G reactants
then solve for K
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