Advertisements

Welcome to My Chemistry Tutor

Welcome, Guest. Please login or register.
Did you miss your activation email?

Login with username, password and session length

Search for Answers

Custom Search
Use our free chemistry search to search thousands of chemistry homework answers and tutorials

Ask a Question

If you did not find the answer to your chemistry question, join the community and ask for help.

Help Other Students

If you received chemistry help here why not try to help other students. You might undertand something that your peers are having trouble with. If you are in college chemistry you can likely help a high school chemistry student

Manipulating Equilibrium Constant Expressions

Pages: [1]
  Print  
Author Topic: Manipulating Equilibrium Constant Expressions  (Read 556 times)
bluedolfinswimmer13
Labrat
*
Posts: 12




« on: January 27, 2010, 05:49:34 PM »

Hello. I have chem homework on this topic and I have completed the first few problems okay but now for the rest of the homework i'm stuck on where to go. I can set up the problem but im not sure how to procede,

Calculate K for the reaction:
Fe + H20 ---> FeO + H20
             <---     

Given:

H2O + CO ----> H2 + CO2    K= 1.6
              <----

FeO + CO ----> Fe + CO2     K= 0.67
              <----

Any help on how to complete problems like this one would be greatly appreciated, thank you


Logged
freezard7734
Labrat
*
Posts: 16




« Reply #1 on: January 27, 2010, 08:03:03 PM »
1

Since the equilibrium constant is the product of the concentrations of the products raised to the power of their coefficients divided by product of the concentrations of the reactants raised to the power of their coefficients.
So reversing a reaction will give you the inverse of the K constant.
And "adding" two reactions together will give you the product of the individual K constants.
So for example, if A --> B has K1, B --> A has K-1
And if C --> D has K2, A + C --> B + D has K1*K2

I hope that helps.
hey
Logged
Pages: [1]
  Print  

 
Jump to:  

* Share this topic...
In a forum
(BBCode)
In a site/blog
(HTML)

Powered by MySQL Powered by PHP Powered by SMF 1.1.11 | SMF © 2006-2009, Simple Machines LLC Valid XHTML 1.0! Valid CSS!
MyChemistryTutor.com

Idea by BJR Technologies