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Finding the mole fraction

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Author Topic: Finding the mole fraction  (Read 503 times)
Katelyn
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« on: January 29, 2010, 01:13:53 PM »

Acetone, C3H6O, is the main ingredient of nail polish remover.  A solution is made by adding 35.0 mL of aceton (density=0.790 g/mL) to 50.0 mL of ethyl alcohol, C2H6O (density=0.789 g/mL).  Assuming volumes are additive, calculate

a. The volume percent of acetone in the solution:   

b. The volume percent of ethyl alcohol in the solution: 

c. The mole fraction of acetone in the solution:

Help! I don't get how to get the mole fraction


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kingchemist
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« Reply #1 on: January 29, 2010, 02:05:34 PM »
1

Use density of acetone to find the mass of 35.0 mL. (mass = density x volume)
Use the molar mass of acetone to find the number of moles of acetone in the calculated mass (no. of moles = mass/molar mass)

Do the same for ethyl alcohol.

Add moles of acetone to moles of ethyl alcohol to give total moles present.
Mole fraction of acetone = moles of acetone/total moles.
Mole fraction of ethyl alcohol = moles of ethyl alcohol/total moles
hey
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'Chemistry is not just the study of matter; Chemistry is the study which matters!' - Kingchemist
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